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1)multimea aritmetica a tuturor elementelor multimii C ={12,14,16,18}
2)abcd,unde a,b, c si d sunt numere naturale consecutive



Răspuns :

1)Ma=12+14+16+18/4=60/4=15
2)1234,2345,3456,4567,5678,6789,9876,8765,7654,6543,5432,4321,3210