[tex] A_{laterala} = \frac{ P_{b}* ap }{2}= \frac{32*4 \sqrt{3} }{2} = 16*4 \sqrt{3} = 64 \sqrt{3} cm^{2} \\ P_{b}=4l =4*8=32 cm \\ triunghi VBM;m(M)=90grade=\ \textgreater \ (T.P ) VM^{2} = VB^2-BM^2 \\ VM^2=8^2-4^2 =\ \textgreater \ VM^2=64-16=\ \textgreater \ VM^2=48 =\ \textgreater \ VM= \sqrt{48} \\ VM=4 \sqrt{3} \\ VM=ap[/tex]
