x²+4x+3=x²+x+3x+3=x(x+1)+3(x+1)=(x+1)(x+3)
x²+2x-3=x²+3x-x-3=x(x+3)-(x+3)=(x+3)(x-1) raportul dupa simplificare este = cu
x+1/x-1 -2/x+1 -7/(x+1)(x-1) aducem la acelasi numitor
(x+1)(x-1)-2(x-1)-7 totul supra (x+1)(x-1)
x²-1-2x+2-7 totul supra (x+1)(x-1)
x²-2x-6 supra (x+1)(x-1) :1/(x+1)(x-1)= x²-4
x²-2x-6 supra (x+1)(x-1) *(x+1)(x-1)=x²-4 prin simplificare obtinem
x²-2x-6=x²-4 se simplifica x² si obtinem
-2x-6=-4
-2x=2
x=-1
