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[tex] \frac{4x+1}{3} = \frac{x-5}{4} [/tex]
[tex] \frac{1}{2} + \frac{2x-5}{4} [/tex]
[tex] \frac{7x-5}{3} - \frac{4x+1}{2} =0[/tex]



Răspuns :

16x+4=3x-15         x=-29/13
=?
14x-10-12x-3=0    x=13/2