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{10la puterea3+10la puterea2*[10+(5la puterea2-x):5]}:20la puterea2=6 aflati x numar natural



Răspuns :

{10³+10²·[10+(5²-X):5]}:20²=6
{1000+100·[10+(25-X)/5]}:400=6
{1000+100·[10+5-X/5]=6·400
[1000+1000+500-100X/5]=2400
2500-20X=2400
-20X=2400-2500
-20X=-100    (-1)
X=100/20
X=5