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calculati aria unui triunghi ABC ,daca BC=8√3 , AC=12√6 si m(unghiuluiC)=45° (rezolvarea intreaga daca se pote ..............multumesc mult

Răspuns :

[tex]A= \frac{AC*BC*sinC}{2} [/tex]
[tex]A= \frac{12 \sqrt{6}*8 \sqrt{3}*sin45 }{2} = \frac{96 \sqrt{18}* \frac{ \sqrt{2} }{2} }{2} [/tex]
A=[tex] \frac{96 \sqrt{36} }{4} = \frac{96*6}{4} = \frac{576}{4} =144[/tex]