👤

rezolvati inecuatia

2(x+1)≤4-3(x-2)
va rog imi trebuie urgent,sa fie corect va rog mult dau coroana


Răspuns :

2x+2≤4-3x+6
2x+3x≤10-2
5x≤8
x≤8:5
2(x+1) ≤ 4-3(x-2)
2x +2 ≤ 4-3x+6
2x+3x ≤ 4+6-2
5x ≤  8
x ≤  [tex] \frac{8}{5} [/tex]