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un calator a parcurs 68kmdin trei zile.
stiind ca in primele doua zile a parcurs 48km,iar in ultimele doua zile a parcurs 36km,aflati cati kilometri a parcurs calatorul in fiecare zi.


Răspuns :

68-48=20 km in a treia zi
68-36=32 km prima zi
68-(20+32)=
68-52=16 km in a doua zi
I+II+III=68
I+II=48
II+III=36
48+III=68
III=68-48=20 KM IN A TREIA ZI
II+III=36 ATUNCI II=36-20=16 IN A DOUA ZI
I+II=48 ATUNCI I=48-16=32 IN PRIMA ZI