Cateta [MP] se opune unghiului de 30* => [tex]MP= \frac{PN}{2}=6(cm). [/tex]
Aplic teorema lui Pitagora in ΔMNP:
[tex] MP^{2}+MN ^{2}= PN^{2}=>MN= \sqrt{PN ^{2}- MP^{2} } = \sqrt{144-36} = \\ = \sqrt{108}= 6\sqrt{3} (cm). [/tex]
[tex] P_{MNP}=MN+NP+MP= 6\sqrt{3}+12+6=18+6 \sqrt{3}=6(3+ \sqrt{3} )[/tex] (cm).
