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ce cantitate de caldura degaja un bec de 25W in timp de 1 ora ?

Răspuns :

P=25 W
t=1 h
  =3600 s
-----------------------/-------
L=?
-----------------------//------
[tex]P=\frac{L}{t}[/tex]
L=Q=P×t 
Q=25W × 3600 s
Q=90000 J

P = 25W
t = 1h = 3600s
Q- ?

P = L / t⇒L = Q = P * t

Q = P * t = 25W * 3600s = 90000J

R/S: Q = 90000J