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Daca BC = 25cm si sinC=3 supra 5, calculati BC , AC , cosB, tgC

Răspuns :

sin C=AB/BC
3/5=AB/25
AB=25x3/5=15 cm
AC=√(25²-15²)=√(625-225)=√400=20 cm
cosB=AB/BC=15/25=3/5
tg C=AB/AC=15/20=3/4