ΔADE≈ΔABC⇒prin teorema lui Thales
AD/AB=AE/AC
3/8=AE/24
AE=3*24/8=3*3=9
EC=AC-AE
=24-9=15
2x+1/x-1 *1-x²/1-3x²
2x+1/x-1 * -(x²-1)/3x²-1
2x+1/x-1 *-(x-1)(x+1)/3x²-1 se simplifica si ne da
-(2x+1)(x+1)/3x²-1
-(2x²+2x+x+1)/3x²-1
-2x²-3x-1/3x²-1
-2x²-2x-x-1/3x²-1
-2x(x+1)-(x+1)/3x²-1
-(2x+1)(x+1)/3x²-1
-(2x+1)(x+1)/x²-1+2x²
-(2x+1)(x+1)/(x-1)(x+1)+2x²
-(2x+1)/(x-1)+2x²