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a)x²-8x+12=0 
b)x²-3x-4=0


Răspuns :

a)x²-8x+12=0
Δ=64-48=16
x₁=(8-4)/2=2
x₁=2
x₂=(8+4)/2=6
x₂=6

b)x²-3x-4=0
Δ=9+16=25
x₁=(3-5)/2=-1
x₁=-1
x₂(3+5)/2=4
x₂=4