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Efectuati:  √108·(√48-√243)+6√2 (√288-√200)=?

Răspuns :

[tex] \sqrt{108} *( \sqrt{48} - \sqrt{243} )+6 \sqrt{2} *( \sqrt{288} - \sqrt{200} )=\\ =6 \sqrt{3} *( 4\sqrt{3} -9 \sqrt{3} )+6 \sqrt{2} *(12 \sqrt{2} -10 \sqrt{2} )\\ =6 \sqrt{3} *-5 \sqrt{3} +6 \sqrt{2} *2 \sqrt{2} \\ =-30*3+12*2\\ =-90+24\\ \boxed{=-66}[/tex]