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3(√3-1)²-√3(√3-6)-(√11-√2)(√11+√2) va rog frumos

Răspuns :

  3(√3-1)²-√3(√3-6)-(√11-√2)(√11+√2) =
=3(3-2√3+1)-3+6√3-(11-2) =
=3(4-2√3)-3+6√3-9 =
=12-6√3-3+6√3-9 =0