fractia este subunitare <=> x+y+1<7
=> x+y<6
=>perechile pot fi:
->pt x+y=5
x=0, y=5
x=1, y=4
x=2, y=3
x=3, y=2
x=4,y=1
x=5, y=0
->pt x+y=4
x=0, y=4
x=1, y=3
x=2, y=2
x=3, y=1
x=4, y=0
->pt x+y=3
x=0, y=3
x=1, y=2
x=2, y=1
x=3, y=0
->pt x+y=2
x=0, y=2
x=1, y=1
x=2, y=0
->pt x+y=1
x=0, y=1
x=1, y=0
->pt x+y=0
x=0, y=0
pentru x diferit de y=> (x, y)={(0, 5), (1, 4), (2,3),(3, 2), (4, 1), (5, 0), (0, 4), (1, 3), (3, 1), (4, 0), (0, 3), (1, 2), (2,1),(3, 0), (0, 2), (2, 0), (0,1), (1,0)=18 perechi
Asa se face. Nu stiu de unde sunt 35 de numere. Mie mi-au dat 18 cu x diferit de y.
