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Deterimnati numerele reale x si y, stiind ca x²+y²+5= 2(√3x-√2y). Va multumesc! SARBATORI FERICITE!

Răspuns :

[tex] x^{2} + y^{2}+5=2* \sqrt{3}x -2* \sqrt{2}y<=> (x^{2} - 2* \sqrt{3}x+3) [/tex] + [tex] (y^{2} +2* \sqrt{2} y+2)=0<=> (x- \sqrt{3}) ^{2} + (y+ \sqrt{2}) ^{2} =0....[/tex]