[tex]x\to masura \ \angle \\\\\\ 180^0-x \to suplementul \ \angle \\\\ \frac{180^0-x}{5} \to a5a \ parte \ din \ suplement \\\\ x^{(5}-36^0^{(5}= \frac{180^0-x}{5} \\\\ 5x-180^0=180^0-x \\\\ 5x+x=180^0+180^0 \\\\ 6x=360^0 \ |:6 \\\\ \boxed{x=60^0}[/tex]
