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Stiind ca :
a la puterea 2 + b la puterea 2 - 8b -4a + 20 = 0

unde a,b apartine R , aflati a si b !!!


Răspuns :

[tex]a^2+b^2-8b-4a+20=0 \\\\ a^2-4a+4+b^2-8b+16=0 \\\\ (a-2)^2+(b-4)^2=0 \\\\ |a-2|+|b-4|=0 \\\\ a-2=0 \ \ \ \ \ AND \ \ \ \ b-4=0 \\\\ \boxed{a=2} \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \boxed{b=4}[/tex]