👤

Daca x+y=47 si z=23, calculati 2z+3z+2y

Răspuns :

2x+3z+2y=2(x+y)+3z=2*47+3*23=94+69=163
x+y=47 Ix2
z=23 Ix3
2x+2y=94
3z=69
2x+2y+3z=94+69
2x+2y+3z=163