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Rezolvați in Q ecuația: x+2x+3x+...+100x=-1+2-3+4-...-201+202.


Răspuns :

[tex]x+2x+3x+...+100x=-1+2-3+.......-201+202 \\ x(1+2+3+...+100)=1+1+1+...+1(1~de~101~ori) \\ x* \frac{100(100+1)}{2}=101 \\ x*50*101=101 \\ x*50=1 \\ x= \frac{1}{50} [/tex]