a) (x+1+x+3+x+5)/3=47
(3x+9)=47*3
3x+9=141
3x=132
x=132/3
x=44
Deci:primul numar este: x+1=45 , al doilea: x+3=47, al treilea x+5=49.
b) (x+x+2+x+4)/3=334
3x+6=334*3
3x+6=1002
3x=1002-6
3x=996
x=332
Deci: primul numar este x=332,al doilea:x+2=334,al treilea:x+4=336.
c) (a+b+c)/3=250
b=a-12
b/c=3 rest 5 -> b=3c+5 =>c=(b-5)/3 -> c=(a-17)/3
a+b+c=250*3
a+b+c=750
a+a-12+c=750
2a+c=762
2a+(a-17)/3=762
6a+a-17=2286
7a=2303
a=329
b=a-12=329-12=317
c=(a-17)/3=(329-17)/3=312/3=104
d) (a+b+c)/3=604
a/b=3 rest 7 -> a=3b+7
c/b=2 rest 5 ->c=2b+5
a+b+c=604*3
a+b+c=1812
3b+7+b+2b+5=1812
6b=1800
b=300
a=300*3+7=907
c=2*300+5=605
/ reprezita operatia de impartire si * operatia de inmultire in cazul in care nu sti.
