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Calculati: 3a+5b+4c+1 ...daca a+b=12 ..si b+2c=7

Răspuns :

3a+5b+4c+1= 3a+3b+2b+4c+1=3(a+b)+2(b+2c)+1=3x12+2x7+1=36+14+1=51




a+b=12 /*3
b+2c=7/*2
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3a+3b=36
2b+4c=14            +
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3a+5b+4c=50/ +1
3a+5b+4c+1=51