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calculati f(1) ,f(3),f(5) ,daca: f:N->Z , F(x)=(modulul lui x)+2

Răspuns :

F(x)=IxI+2=>
F(1)=I1I+2=1+2=3;
F(3)=I3I+2= 3+2=5;
F(5)=I5I+2= 5+2= 7;