a) 2x+(3-6x)=-17
2x+3-6x=-17
-4x=-20
x=5
b)2(x+1)=3(x-1)
2x+2-3x+3=0
-x=-5
x=5
c)2x(x+1)=4-(1-2x)
[tex]2 x^{2} +2x-4+1-2x=0[/tex]
[tex]2 x^{2} =3[/tex]
[tex] x^{2} = \frac{3}{2} [/tex]
|x|=[tex] \sqrt{ \frac{3}{2} } [/tex]
x=-[tex] \sqrt{ \frac{3}{2} } [/tex] sau x=[tex] \sqrt{ \frac{3}{2} } [/tex]
d)15-[tex] \frac{x}{6} -2x+ \frac{16}{5} =1[/tex]
[tex]- \frac{x}{6} -2x=1-15- \frac{16}{5} [/tex]
[tex]- \frac{13}{6}x=- \frac{86}{5} [/tex]
x=[tex] \frac{86}{5} [/tex]×[tex] \frac{6}{13} = \frac{516}{65} [/tex]
