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suma a cinci nr naturale consecutive este 125.aflati numerele
VAROG REPEDE


Răspuns :

a+a+1+a+2+a+3+a+4=125
a×5+10=125
a×5=125-10
a×5=115
a=115:5
a=23
v:23+24+25+26+27=125
a+a+1+a+2+a+3+a+4=125
a×5+10=125
a×5=125-10
a×5=115
a=115:5
a=23
v:23+24+25+26+27=125

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