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Fara metode babesti. Mersi.

Fara Metode Babesti Mersi class=

Răspuns :

Știi că n(M1UM2)=nM1+nM2-n(M1∩M2)

n(AUB)+nC-n((AUB)∩C)=
n(AUB)+nC-n((A∩C)U(B∩C))=
n(AUB)+nC-(n(A∩C)+n(B∩C)-n((A∩C)∩(B∩C)))=
nA+nB-n(A∩B)+nC-n(A∩C)-n(B∩C)+n(A∩B∩C)=
nA+nB+nC-n(A∩B)-n(A∩C)-n(B∩C)+n(A∩B∩C)