👤

Paralelogramul ABCD are DB _I_ AD . Daca AB = 16 cm si DB = 15 cm , sa
se afle Perimetrul ABCD si Aria ABCD . HELP me please !


Răspuns :

ΔADB, mD=90
AB²=AD²+DB²
AD²=256-225
AD²=31
AD=√31
P =2AD+2DC
P=2√31+32
Construiesti inaltimea DM
DM=[tex] \frac{AD*DB}{AB} [/tex]
DM=[tex] \frac{15 \sqrt{31} }{16} [/tex]
Aria= DM*AB
aRIA=[tex] \frac{15 \sqrt{31} }{16} *16= 15 \sqrt{31} [/tex]