[tex]Notam\ AB=6cm,\ DC=4 cm\\
Fie\ M\ mijlocul\ lui AD,\ iar\ N\ mijlocul\ lui\ BC.\\
MN=\frac{AB+CD}{2}\\\\
MN=\frac{6+4}{2}=\frac{10}{2}=5 cm\\
MN\ int\ AC=\{P\}\\
MN\ int.\ BD=\{Q\}\\
In\ \Delta ABC:[MP]lm=\ \textgreater \ MP=\frac{DC}{2}\\
Deci\ MP=2 cm\\
In\ \Delta BCD:[QN]lm=\ \textgreater \ QN=\frac{DC}{2}=2cm\\
PQ=MN-MP-QN\\ PQ=5-2-2=1 cm[/tex]
