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efectuati calculele:√108×(√432-√75-√48)= va rog si explicat dac se poate multumesc


Răspuns :

[tex] \sqrt{108} ( \sqrt{432} - \sqrt{75} - \sqrt{48} )=6 \sqrt{3} (12 \sqrt{3} -5 \sqrt{3} -4 \sqrt{3} )= \\ =6 \sqrt{3} (7 \sqrt{3} -4 \sqrt{3} )=6 \sqrt{3} \cdot 3 \sqrt{3} =18 \cdot 3=54[/tex]