Algebric, se rezolva astfel:
a= prima zi
b= a doua zi
c= a treia zi
a+b+c= 96kg
a=13+b
c=32+b
Inlocuim in relatie:
13+b+b+32+b=96
3b+45=96/-45
3b=51/:3
b=17
a=13+17
a=30
c=32+17
c=49
30+17+49=96
Prin segmente:
1 |______|__13__|
2 |______| } =96
3 |______|_____32______|
1 |______|
2 |______| } = 96-(13+32)
3 |______| =51
3 zile impartite la 51
51:3=17
1 |___17___|__13__|
2 |___17___| } =96
3 |___17___|_____32______|
Sper ca ti-a fost de folos ;)
