1.[tex]divizori _{48}={1;2;3;4;6;8;12;16;24;48} \\ probabilitate= \frac{10}{60} = \frac{1}{6} [/tex]
2.[tex]nr.prime.zar=2,3,5 \\ probabilitate= \frac{3}{6} = \frac{1}{2} [/tex]
3.[tex]probabiliate= \frac{12}{21-1+12}= \frac{12}{32}= \frac{3}{8} [/tex]