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Calculati media aritmetica a numerelor: 2 supra 5; 1,(3) si 22 supra 6

Răspuns :

[tex]\displaystyle m_a= \frac{ \frac{2}{5}+1,(3)+ \frac{22}{6} }{3} = \frac{ \frac{2}{5} + \frac{4}{3} + \frac{22}{6} }{3} = \frac{ \frac{12+40+110}{30} }{3} = \frac{ \frac{162}{30} }{3} = \\ \\ = \frac{162}{30} :3= \frac{162}{30} \times \frac{1}{3} = \frac{162}{90} = \frac{9}{5} [/tex]