[tex]\displaystyle a).0,(18)= \frac{18}{99} ^{(9} = \frac{2}{11} \\ \\ b).3,(2)= \frac{32-3}{9} = \frac{29}{9} \\ \\ c).6,1(8)= \frac{618-61}{90} = \frac{557}{90} \\ \\ d).5,12(18)= \frac{51218-512}{9900} = \frac{50706}{9900} ^{(9} = \frac{5634}{1100} ^{(2} = \frac{2817}{550} \\ \\ e).25,1(378)= \frac{251378-251}{9990} = \frac{251127}{9990} ^{(9} = \frac{27903}{1110} ^{(3} = \frac{9301}{370} [/tex]