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Explicita modulul
|(3-√2)la puterea 2|


Răspuns :

[tex]|(3- \sqrt{2})^{2}| \\ | 3^{2}-2*3* \sqrt{2}+ \sqrt{ 2^{2} }| \\ |9-6 \sqrt{2}+2| \\ |11-6 \sqrt{2}| \to 11-6 \sqrt{2} [/tex]
[tex]|(3- \sqrt{2} )^2|=|3^2 -2 \cdot 3 \cdot \sqrt{2} + \sqrt{2} ^2|=|9-6 \sqrt{2} +2|= \\ =|11-6 \sqrt{2} |=11-6 \sqrt{2} [/tex]