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calculati suma s=4+8+12+......+2012

Răspuns :

[tex]\displaystyle 4+8+12+...+2012 =4(1+2+3+...+503) = \\ \\ =4 \cdot \frac{503(503+1)}{2} =4 \cdot \frac{503\cdot 504}{2} =4 \cdot \frac{253512}{2} =4 \cdot 126756=507024[/tex]