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Cum se rezolva urmatoarea inecuatie |x^2-3x+2|<=4x+2.

Răspuns :

[tex] |x^{2} -3x+2| \leq 4x+2 \\ x^{2} -3x+2 \leq 4x+2 \\ x( x-3)+2 \leq 4x+2 \\ x( x-3) \leq 4x \\ ( x-3) \leq 4 \\ x \leq 7[/tex]