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Sa se demonstreze ca A=B
Ex 15
Multumesc !


Sa Se Demonstreze Ca AB Ex 15 Multumesc class=

Răspuns :

[tex] \displaystyle\frac{x^{10}+3}{2x^2}\in Z=\ \textgreater \ 2\cdot \frac{x^{10}+3}{2x^2}\in Z=\ \textgreater \ \\ \frac{x^{10}+3}{x^2}\in Z=\ \textgreater \ (x^8+ \frac{3}{x^2} )\in Z=\ \textgreater \ \frac{3}{x^2} \in Z=\ \textgreater \ x=\pm1=\ \textgreater \ \\ A=\{-1,1\}\\ \frac{x^{10}+2}{3x^2}\in Z=\ \textgreater \ 3\cdot \frac{x^{10}+2}{3x^2}\in Z=\ \textgreater \ \\ \frac{x^{10}+2}{x^2}\in Z=\ \textgreater \ (x^8+ \frac{2}{x^2} )\in Z=\ \textgreater \ \frac{2}{x^2} \in Z=\ \textgreater \ x=\pm1=\ \textgreater \ \\ B=\{-1,1\}\\A=B[/tex]