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AB=4 cm
BC=6 cm
m(B)=30 de grade
1) A triunghiului=?
2) Raza=? (teorema cosinusului)


Răspuns :

A=1/2*AB*BC*sin30=1/2*4*6*1/2=4cm^2
[tex] AC^{2} = AB^{2}+ BC^{2}-2AB*BC*cosB=16+ 36-2*4*6* \frac{ \sqrt{3} }{2} [/tex]
[tex] AC^{2} =52-24 \sqrt{3} [/tex]