11,1g substanta.................3,36L (c.n)
x g substanta................... 22,4L (c.n)
x=22,4*11,1/3,6=74g substanta
insa in conditii normale Msubstantei=74g/mol
:0,5
C: 24/12=2 4
H: 5/1=5 10
O: 8/16=0,5 1
C₄H₁₀O
Eu iti voi scrie toti izomerii si numarul il calculezi tu:
CH₃-CH₂-CH₂-CH₂-OH 1-butanol
CH₃-CH(CH₃)-CH₂-OH 2metil 1propanol
CH₃-CH(OH)-CH₂-CH₃ prezinta izomerie optica ( 2 izomeri + si - ) 2-butanol
CH₃-C(CH₃){OH}-CH₃ 2metil-2butanol
