mHNO3=32*200/100=64g HNO3
mH2SO4=60*200/100=120g H2SO4
mapa=8*200/100=16g apa
78g.......63g................................18g
C6H6 + HNO3 -> C6H5-NO2 + H2O
78g.......63g................................18g
din cele 64g HNO3 a ramas 1g HNO3 si s-au adaugat 18g apa
amestecul final contine:
120g H2SO4, 1g HNO3 si 34g H2O
155g amestec...............100%
120g H2SO4......................x%
x=120*100/155=77,42% => D)