Nu iese, da x=45/8, ai gresit iar cerinta.
[tex] \frac{2x-1}{2} + \frac{x}{3} =7[/tex], amplificam odata cu3,2 si 6 sa ajungem la acelasi numitor, => [tex] \frac{6x-3}{6} [/tex] + [tex] \frac{2x}{6} [/tex] = [tex] \frac{42}{6} [/tex]. =>[tex] \frac{8x-3}{6} = \frac{42}{6} [/tex] => 8x-3=42 => 8x=45 => x= [tex] \frac{45}{8} [/tex]=5.625. Pentru cultura ta generala :). yoandrey17.
